Solving x values for logarithmic equation.

[Belinda]

I would really appreciate some help with this problem. I don't know how to factor or use log to get the x values. I haven't run into a problem like this before.

x²e^2x + 6xe^2x − e^2x = 0

Thanks for the help in advance.

EDIT: SOLVED

x = .1623

x = -6.1623

 

[galactus]

Very good that you got it. But, perhaps some friendly advice for aestheic purposes.

Instead of writing your solution as a decimal, write it in closed form as

\(\displaystyle x=\pm \sqrt{10}-3\)