Special Theory of Relativity

logistic_guy

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What is the momentum of a proton traveling at v=0.85c\displaystyle v = 0.85c?
 
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p=mv1v2c2=1.67×1027(0.85)(299792458)1(0.85)2=8.08×1019 kgm/s\displaystyle p = \frac{mv}{\sqrt{1-\frac{v^2}{c^2}}} = \frac{1.67 \times 10^{-27}(0.85)(299792458)}{\sqrt{1 - (0.85)^2}} = 8.08 \times 10^{-19} \ \text{kg} \cdot \text{m/s}
 
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