Hi all I have a ? I just can't see it. please note (^2) = squared
the Law of cosine I understand- 3 sides of a triangle (a,b,c) 1 angle. so a^2=b^2+c^2-2(b)(c)cos(angle)
here is my problem have side (a) and side (b) and the angle between the 2. (a)= 4 (b)= 5 (c)=? the angle between the (c,b)=30
so my formula will be 3^2=5^2+c^2-2(5)(c)cos30
i am having difficulty here as I don't no what to do with the c^2 or the (c) I not I need to get the c^2 on the out side I just can't figure out how?
please leave step by step as to how to get this solved and to get (c) by its self. I no how to solve if it was C^2=5^2+3^2-2(5)(3)cos30 where (c) would already be on the outside.
3^2=5^2+c^2-2(5)(c)cos30°
9=25+(c^2 )-10(c)cos30°
the Law of cosine I understand- 3 sides of a triangle (a,b,c) 1 angle. so a^2=b^2+c^2-2(b)(c)cos(angle)
here is my problem have side (a) and side (b) and the angle between the 2. (a)= 4 (b)= 5 (c)=? the angle between the (c,b)=30
so my formula will be 3^2=5^2+c^2-2(5)(c)cos30
i am having difficulty here as I don't no what to do with the c^2 or the (c) I not I need to get the c^2 on the out side I just can't figure out how?
please leave step by step as to how to get this solved and to get (c) by its self. I no how to solve if it was C^2=5^2+3^2-2(5)(3)cos30 where (c) would already be on the outside.
3^2=5^2+c^2-2(5)(c)cos30°
9=25+(c^2 )-10(c)cos30°