splitting the numerator

[jackmac]

How do I explain this? Am I expanding the fraction, decomposing the fraction or extracting a from the fraction?

. . . . .\(\displaystyle \dfrac{6a}{2}\, =\, \dfrac{6}{2}\, a\)

 

[Ishuda]

How do I explain this? Am I expanding the fraction, decomposing the fraction or extracting a from the fraction?

. . . . .\(\displaystyle \dfrac{6a}{2}\, =\, \dfrac{6}{2}\, a\)

You are just re-writing the expression in an equivalent form. If you had to have a different expression for it I guess I probably say 'partially decomposing the fraction' although some might disagree with the 'partial' part of it.