square root again

[dkarolasz]

sqrt-121

I know that the sqrt121 is 11 but not sure what to do with the neg sign

would it be -sqrt11

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this I think I got but then again I'm not sure

18+sqrt567/9

18+9sqrt7/9

27sqrt7/9 reduced

3sqrt7 <-- my final answer????

 

[morson]

\(\displaystyle sqrt{-121}\) is not a real number.

You were doing well until your third line, for the next one. Leave it as \(\displaystyle 18 + sqrt{7}\)

 

[dkarolasz]

18+sqrt567/9

18+9sqrt7/9

27sqrt7/9 reduced

3sqrt7 <-- my final answer????



18 + sqrt 7/ 9

I reduce to get

2sqrt7 <----is that right

 

[Denis]

18+sqrt567/9
18+9sqrt7/9
27sqrt7/9 reduced
3sqrt7 <-- my final answer????

18 + sqrt 7/ 9
I reduce to get
2sqrt7 <----is that right

WHOA!
Post again CLEARLY: put BRACKETS around what's being squared:
like, is that sqrt(567) / 9 or sqrt(567 / 9)?
and is that sqrt(7) / 9 or sqrt(7 / 9) ?

Warning: there are serious basic errors in your "reducing"; what grade are you in?

 

[dkarolasz]

18+(sqrt567)/9

18+(9sqrt7)/9

27sqrt7/9 reduced

3sqrt7 <-- my final answer????

18 + (sqrt 7)/ 9

I reduce to get

2sqrt7 <----is that right

You don't want to know what grade I'm in, I've never been good in Math EVER!!!
I know you don't want to here this but I HATE MATH.. always been hard for me

 

[Denis]

18+(sqrt567)/9
18+(9sqrt7)/9
27sqrt7/9 reduced
3sqrt7 <-- my final answer????
I know you don't want to here this but I HATE MATH.. always been hard for me

AGAIN: DO NOT show as (sqrt567): show this way: sqrt(567) ; OK ? :shock:

so let's go over that one (and I suggest you use similar procedure to SHOW):
18 + sqrt(567) / 9
= 18 + sqrt(81 * 7) / 9
= 18 + 9sqrt(7) / 9
= 18 + sqrt(7) : final answer

Notice that the 18 is NOT divided by 9.
IF the 18 SHOULD BE divided by 9, then you MUST show this way:
(18 + sqrt(567)) / 9
= (18 + sqrt(81 * 7)) / 9
= (18 + 9sqrt(7)) / 9
= 2 + sqrt(7) : final answer

NOTE: keep HATING MATH and you'll keep having problems...