Square Wave Form Differentiation

spacekeys

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Plot this function from t=0 to t=0.1 and determine where this function x(t) is differentiable.

X(t) = 1+(4/pi)(sin(2pi50t)+(1/3)sin(6pi50t)+(1/5)sin(10pi50t))

I have entered the equation into WolframAlpha. Can somebody help me determine where this function is differentiable?

http://www.wolframalpha.com/input/?...in(6pi50t)+(1/5)sin(10pi50t))+from+t=0+to+0.1

Also, find the square wave function that x(t) approximates.
 
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Plot this function from t=0 to t=0.1 and determine where this function x(t) is differentiable.

X(t) = 1+(4/pi)(sin(2pi50t)+(1/3)sin(6pi50t)+(1/5)sin(10pi50t))

I have entered the equation into WolframAlpha. Can somebody help me determine where this function is differentiable?

http://www.wolframalpha.com/input/?...in(6pi50t)+(1/5)sin(10pi50t))+from+t=0+to+0.1

Also, find the square wave function that x(t) approximates.

do you know of any point where y = sin(x) is not differentiable?
 
No, there isn't any point on y = sin(x) that is not differentiable right? Does that mean that the function I was given is differentiable everywhere?

You make that decision from your knowledge of "definition of differentiability".
 
You make that decision from your knowledge of "definition of differentiability".

That is why I posted this question, because I needed help with that decision. I don't understand the definition perfectly. I understand it enough to know that sin(x) is differentiable everywhere, but I am unsure about the function I was given. That is why I posted this thread.
 
For a function of one variable, f(x), "differentiable at x= a" means that the derivative exists at x= a, which means that limh0f(a+h)f(a)h\displaystyle \lim_{h\to 0}\frac{f(a+ h)- f(a)}{h} exists.
 
...X(t) = 1+(4/pi)(sin(2pi50t)+(1/3)sin(6pi50t)+(1/5)sin(10pi50t))

I have entered the equation into WolframAlpha. Can somebody help me determine where this function is differentiable?...

We know sin (x) is differentiable with respect to (wrt) x as is sin(t) wrt t, sin (z) wrt z, etc. Is sin(2 π\displaystyle \pi 50 t) differentiable wrt t? Yes, just let x = 2 π\displaystyle \pi 50 t and we have sin(x) which is differentiable wrt x and, since x is differentiable wrt t, by the chain rule we have sin(x) is differentiable wrt t.
 
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