Standard Form

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HorseWhisperz

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Joined
Apr 14, 2009
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Okay, so I tried looking online for how to put it into standard form but I've had no luck. An example is:

y = -1/11 (x +10)[sup:1bsxly5x]2[/sup:1bsxly5x] +16

I was to find the vertex, which I did (-10, 16) and put into standard form, identifying a, b, and c.

I know that the formula for standard form is y=ax[sup:1bsxly5x]2[/sup:1bsxly5x]+bx+c, but I don't know how to rearrange it into such. Please, any assistance is greatly appreciated. :)
 
HorseWhisperz said:
Okay, so I tried looking online for how to put it into standard form but I've had no luck. An example is:

y = -1/11 (x +10)[sup:3mnbtxkq]2[/sup:3mnbtxkq] +16

I was to find the vertex, which I did (-10, 16) and put into standard form, identifying a, b, and c.

I know that the formula for standard form is y=ax[sup:3mnbtxkq]2[/sup:3mnbtxkq]+bx+c, but I don't know how to rearrange it into such. Please, any assistance is greatly appreciated. :)
Click to expand...

Expand (x+10)[sup:3mnbtxkq]2[/sup:3mnbtxkq] using:

(a+b)[sup:3mnbtxkq]2[/sup:3mnbtxkq] = a[sup:3mnbtxkq]2[/sup:3mnbtxkq] + 2ab + b[sup:3mnbtxkq]2[/sup:3mnbtxkq]

Then simplify...
 
HorseWhisperz said:
So, by doing that I get x[sup:163unhmh]2[/sup:163unhmh]+ 20x +100, right? And then?
Click to expand...

then you get:

y = -1/11 (x[sup:163unhmh]2[/sup:163unhmh] + 20x + 100) + 16

and simplify.....
 
Oh, thanks.
The answer is y= (-1/11)x[sup:2neacq7g]2[/sup:2neacq7g] - (20/11)x + (76/11)

And how would I find the stretch/compression factor?
 
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