State asymptote equation(s) for y = 1/(x + 3) - 1

[vashi123]

Its pretty easy, I get how asymptotes work and all but I'm stumped on how to write the actual equation for them.

The question is:

State the equations of any asymptote lines from the function y = 1 / (x+3) - 1

If anyone has a calculator handy and could help me out I would appreciate it!

 

[stapel]

If anyone has a calculator handy and could help me out I would appreciate it!

Why would you need a calculator...? :?:

Where is the function undefined? That gives you the vertical asymptote.

As x gets very large, what happens to the fractional part? So what is left as the (approximate) y-value? This gives you the horizontal asymptote.

Eliz.

 

[vashi123]

If anyone has a calculator handy and could help me out I would appreciate it!

Why would you need a calculator...? :?:

Where is the function undefined? That gives you the vertical asymptote.

As x gets very large, what happens to the fractional part? So what is left as the (approximate) y-value? This gives you the horizontal asymptote.

Eliz.

Yeah, i know where it is undefined.., at the -3. But how would I write that? Just X =/= -3? or is there a special y=ax+c or something equation ?

 

[Deleted member 4993]

The line

x = -3

is the vertical asymptote for the given function.

By the way, vertical lines cannot be written in the y = mx+c form - because vertical lines are independent of 'y'.