statisticsisawesome
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2.8 A survey on the drinking habits of adults asked the participants how many days a week they consumed alcohol, as well as the type and quantity of alcohol consumed. Of the 755 adults surveyed, 491 said they consumed alcohol at least twice a week
a) Create a 95% confidence interval for the true proportion of adults who consume alcohol at least twice a week, and interpret the interval
P hat = 491/755
therefore Q hat = 264/755
(491/755) - 1.96*sqrt(((491/755)*(264/755)))/(755))) < P < (491/755) + 1.96*sqrt(((491/755)*(264/755)))/(755)))
= 0.616315509 < P < 0.684346743
therefore we are 95% confident that between 61.63% and 68.44% drink alcohol atleast twice a week
b) Based on your confidence interval, comment on the accuracy of a media report stating that 70% of adults consume alcohol at least twice a week.
Not very accurate since 70% is not within the confidence interval (61.63%, 68.44%)
Can someone please verify if my answers for the above question are correct?
Thanks
a) Create a 95% confidence interval for the true proportion of adults who consume alcohol at least twice a week, and interpret the interval
P hat = 491/755
therefore Q hat = 264/755
(491/755) - 1.96*sqrt(((491/755)*(264/755)))/(755))) < P < (491/755) + 1.96*sqrt(((491/755)*(264/755)))/(755)))
= 0.616315509 < P < 0.684346743
therefore we are 95% confident that between 61.63% and 68.44% drink alcohol atleast twice a week
b) Based on your confidence interval, comment on the accuracy of a media report stating that 70% of adults consume alcohol at least twice a week.
Not very accurate since 70% is not within the confidence interval (61.63%, 68.44%)
Can someone please verify if my answers for the above question are correct?
Thanks