There is a 55 gallon drum with a 40% solution. Another 55 gallon drum has a 100% solution. How many gallons of the 40% drum must be emptied and replaced with the 100% solution to end up with a 55 gallon drum of 75% solution? Please show work with answer and any necessary explanations. Thanks!
story prob: There is a 55 gallon drum with a 40% solution.
- Thread starter ORIOLE1
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Re: story problem
x = # of gallons to pour off and replace.
Equate Solution
55*0.40 - x*0.40 + x*1.00 = 55*0.75 -- Solve for x
Equate NonSolution
55*0.60 - x*0.60 + x*0.00 = 55*0.25 -- Solve for x
Show your work.
Always, I am humored by the student sufficiently careful to copy the problem, even quoting the "show your work" part, but insufficiently astute actually to show some work.
Always, simply equate something. In this case, either the "solution" or the non-"solution".ORIOLE1 said:
x = # of gallons to pour off and replace.
Equate Solution
55*0.40 - x*0.40 + x*1.00 = 55*0.75 -- Solve for x
Equate NonSolution
55*0.60 - x*0.60 + x*0.00 = 55*0.25 -- Solve for x
Show your work.
Always, I am humored by the student sufficiently careful to copy the problem, even quoting the "show your work" part, but insufficiently astute actually to show some work.