Find
\(\displaystyle \frac{d}{dx}\ \int \frac{sin(t^3)x}{t^2}dt\) - the upper boundary for the integral is \(\displaystyle 4+x^4\) and the lower is \(\displaystyle 2+cos^2(x)\)
I wouldn't even know what to search for to learn about this type of integral...
\(\displaystyle \frac{d}{dx}\ \int \frac{sin(t^3)x}{t^2}dt\) - the upper boundary for the integral is \(\displaystyle 4+x^4\) and the lower is \(\displaystyle 2+cos^2(x)\)
I wouldn't even know what to search for to learn about this type of integral...