Stuck on a Trig-Sub - Corner and spiders and reincarnation

[Deleted member 4993]

Since \(\displaystyle \sqrt(x^2) = |x|\) you really can't conclude that \(\displaystyle \dfrac{cos(x)}{\sqrt{sin^2(x) - 1}} =1\)​

From where did you get that:

.......................................................\(\displaystyle \dfrac{cos(x)}{\sqrt{sin^2(x) - 1}} \)

I think you meant:

.......................................................\(\displaystyle \dfrac{cos(x)}{\sqrt{1 - sin^2(x)}} \)

 

[Steven G]

From where did you get that:

.......................................................\(\displaystyle \dfrac{cos(x)}{\sqrt{sin^2(x) - 1}} \)

I think you meant:

.......................................................\(\displaystyle \dfrac{cos(x)}{\sqrt{1 - sin^2(x)}} \)

I'll be in the corner for a bit.

 

[Deleted member 4993]

I'll be in the corner for a bit.

Since [sin²(x)-1] \(\displaystyle \leq \) 0

We'll have to just "imagine" your image in the corner!!

 

[topsquark]

I'll be in the corner for a bit.

I saw a spider over there a little while ago...

-Dan

 

[Steven G]

I saw a spider over there a little while ago...

-Dan

What were you doing in the corner?

 

[topsquark]

Little miss Muffet screamed and I came out. The spider started chasing me so I grabbed her curds and whey and ran away hoping to confuse it and drown it, but the corner got in the whey and it escaped.

All spiders hate me. I think I was a rolled up newspaper in a former life.

-Dan