Stuck on finding values on cos theta and tan theta

Well, cosine is negative in QIII, so use sin2(θ)+cos2(θ)=1sin^2( \theta ) + cos^2( \theta ) = 1 to find cos(θ)cos( \theta ). Once you have that you can calculate tan(θ)tan( \theta ).

-Dan
 
You should know how to do this without choices.
Since you are given choices and the angle is in quadrant III you should look for an answer where cos is negative and tangent is positive.
 
Top