Please show us where you are stuck, so we can come pull you out!
Have you tried sketching the angle and a reference triangle for it? Or, if you prefer, have you tried using any identities? And what in particular makes you unsure of your answer?
Well, cosine is negative in QIII, so use [imath]sin^2( \theta ) + cos^2( \theta ) = 1[/imath] to find [imath]cos( \theta )[/imath]. Once you have that you can calculate [imath]tan( \theta )[/imath].
You should know how to do this without choices.
Since you are given choices and the angle is in quadrant III you should look for an answer where cos is negative and tangent is positive.
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