temperature

[logistic_guy]

How much heat (joules) is required to raise the temperature of $\displaystyle 30.0 \ \text{kg}$ of water from $\displaystyle 15^{\circ}\text{C}$ to $\displaystyle 95^{\circ}\text{C}$?

 

[logistic_guy]

We use the heat transfer equation to solve this problem.

$\displaystyle \Delta Q = mc\Delta T$

where $\displaystyle c$ is the specific heat capacity. For water $\displaystyle c = 4186 \ \text{J/kg} \cdot \text{C}^{\circ}$

Then,

$\displaystyle \Delta Q = (30)(4186)(95 - 15) = \textcolor{blue}{1 \times 10^7 \ \text{J}}$