G gmontalv New member Joined Jan 27, 2006 Messages 13 Mar 5, 2006 #1 f(x) = x g(x) = 3x-1 --- + 12 8 Find f[(g(x)] Can someone walk me through this? also, at what point on a graph of f(x) =6x^2 + 4x - 9 is the slope of the tangent line -2. I need step by step please.[/code]
f(x) = x g(x) = 3x-1 --- + 12 8 Find f[(g(x)] Can someone walk me through this? also, at what point on a graph of f(x) =6x^2 + 4x - 9 is the slope of the tangent line -2. I need step by step please.[/code]
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Mar 5, 2006 #2 gmontalv said: f(x) = x g(x) = 3x-1 --- + 12 8 Find f[(g(x)] Can someone walk me through this? also, at what point on a graph of f(x) =6x^2 + 4x - 9 is the slope of the tangent line -2. I need step by step please.[/code] Click to expand... I'm guessing your functions are ... f(x) = (x/8) + 12 and g(x) = 3x - 1 what's to walk through? f[g(x)] = f(3x-1) = (3x-1)/8 + 12 ----------------------------------------------------------------------- for the second question, find the derivative of f(x) and set f'(x) equal to -2, then solve for x ... the point on the curve will be (x, f(x))
gmontalv said: f(x) = x g(x) = 3x-1 --- + 12 8 Find f[(g(x)] Can someone walk me through this? also, at what point on a graph of f(x) =6x^2 + 4x - 9 is the slope of the tangent line -2. I need step by step please.[/code] Click to expand... I'm guessing your functions are ... f(x) = (x/8) + 12 and g(x) = 3x - 1 what's to walk through? f[g(x)] = f(3x-1) = (3x-1)/8 + 12 ----------------------------------------------------------------------- for the second question, find the derivative of f(x) and set f'(x) equal to -2, then solve for x ... the point on the curve will be (x, f(x))