The age of father is twice as his son´s age. 10 years ago, sum of both ages was ...
Hello. I want to know i did it correctly or not, please. Thanks.
question:-The age of father is twice as his son´s age. 10 years ago, sum of both ages was same as an actual age of father. find the actual age of both?
solution:- let son´s age=x
Father´s age=y
then y=2x
10 years ago:
x-10+y-10=2x
-x+y=20
using y=2x
-x+2x=20
x=20
substituting implies y=40.
Hello. I want to know i did it correctly or not, please. Thanks.
question:-The age of father is twice as his son´s age. 10 years ago, sum of both ages was same as an actual age of father. find the actual age of both?
solution:- let son´s age=x
Father´s age=y
then y=2x
10 years ago:
x-10+y-10=2x
-x+y=20
using y=2x
-x+2x=20
x=20
substituting implies y=40.