The formula 180(n-2) gives the number of degrees in the angles of a convex polygon...

[randy.lahey]

[FONT=&quot]The formula 180(n-2) gives the number of degrees in the angles of a convex polygon because n-2 triangles can be drawn (with no lines crossing) in a polygon with n sides, each triangle containing 180. In how many ways can a convex heptagon be divided into five triangles if each divided into five triangles if each different orientation is counted separately? (Hint: look up the Catalan sequence)[/FONT]

 

[mmm4444bot]

The formula 180(n-2) gives the number of degrees in the angles of a convex polygon because n-2 triangles can be drawn (with no lines crossing) in a polygon with n sides, each triangle containing 180. In how many ways can a convex heptagon be divided into five triangles if each divided into five triangles if each different orientation is counted separately? (Hint: look up the Catalan sequence)

What have you tried, thus far? What are your thoughts? We would like to see your efforts.

 

[randy.lahey]

I have a hard math problem, I have no clue how to do, please show and explain work

[FONT=&quot]The formula 180(n-2) gives the number of degrees in the angles of a convex polygon because n-2 triangles can be drawn (with no lines crossing) in a polygon with n sides, each triangle containing 180. In how many ways can a convex heptagon be divided into five triangles if each different orientation is counted separately?

I have no work for this problem, I have no clue, may someone please help me[/FONT]

 

[Deleted member 4993]

The formula 180(n-2) gives the number of degrees in the angles of a convex polygon because n-2 triangles can be drawn (with no lines crossing) in a polygon with n sides, each triangle containing 180. In how many ways can a convex heptagon be divided into five triangles if each different orientation is counted separately?

I have no work for this problem, I have no clue, may someone please help me

You have posted eight problems in this forum - and not a single line of work!

You really need to show some thought about these problems - so that we know where to begin to help you.

 

[randy.lahey]

You have posted eight problems in this forum - and not a single line of work!

You really need to show some thought about these problems - so that we know where to begin to help you.

I am aware I need to show work, but I just moved from the Canada to the US and I just started school and the concepts are harder than what I have learnt, I am running in circle

 

[Otis]

A convex heptagon is a seven sided convex polygon. A heptagon(seven sided) cannot be divided into five triangles.

A heptagon can be divided into five triangles.

The formula for the number of triangles of a regular polygon is n-2, where n is the number of sides.

Here's a reference

 

[Otis]

In how many ways can a convex heptagon be divided into five triangles if each different orientation is counted separately?

Hi Randy. Go to this site:

http://www.mathopenref.com/polygontriangles.html

Read their explanation about how to divide a regular polygon into triangles. You need to pick a vertex first, then you draw the lines. Yes?

When they mention "each different orientation", they are talking drawing the lines from one vertex, then doing it again from another vertex, and then yet again from another vertex, until it has been done in all possible ways.

Try it. How many ways can you do it?