The largest open interval of the domain over which the function is increasing is...

[lockzero1]

I'm working on quadratic functions and models, and I encountered this question after obtaining the vertex on a quadratic equation and graphing it. I've attached an image of the problem, with all of the components that were previously asked regarding this problem. I don't understand what the question is asking for, and I attempted to give the vertex as an answer.

 

[Deleted member 4993]

I'm working on quadratic functions and models, and I encountered this question after obtaining the vertex on a quadratic equation and graphing it. I've attached an image of the problem, with all of the components that were previously asked regarding this problem. I don't understand what the question is asking for, and I attempted to give the vertex as an answer.View attachment 17394

Look at your answer for part (c) and look at the curve you have drawn.

You can see that the function is increasing from x = 3 to x = \(\displaystyle \infty \)

Now put the above statement in interval notation.

 

[lockzero1]

I still don't get it. I entered [3,∞) and it was wrong

 

[Dr.Peterson]

I still don't get it. I entered [3,∞) and it was wrong

It asked for an open interval. What is the largest open interval within [3,∞) ?

 

[pka]

I still don't get it. I entered [3,∞) and it was wrong

Hint: \([3,\infty)\) is a closed interval.