The Pi constant factor enigma

[Cubist]

Posted on behalf of @Atomisphere Alpha

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In my time playing with the calculator, I could find an approximation which might be useful.

The Pi constant factor enigma.

The only codex for the circle unit is beginning with an approximation of…

Level A
710/113-6=0.2831858407079646017699115044247787610619469026548672566371681415…

Level B
We subtract it from the number 4.
4-0.2831853071795864769252867665590057683943387987502116419498891846...=
3.7168146928204135230747132334409942316056612012497883580501108153…

Level C
3.7168146928204135230747132334409942316056612012497883580501108153…-0.5=
3.2168146928204135230747132334409942316056612012497883580501108153…

Level D
3.2168146928204135230747132334409942316056612012497883580501108153…+9.5=
12.716814692820413523074713233440994231605661201249788358050110815…

Level E
5.25-3.7168146928204135230747132334409942316056612012497883580501108153...(from C)=
1.5331853071795864769252867665590057683943387987502116419498891846…

Level F
1.5331853071795864769252867665590057683943387987502116419498891846…*8=
12.265482457436691815402294132472046147154710390001693135599113476…

Level G
12.265482457436691815402294132472046147154710390001693135599113476..,/2=
6.132741228718345907701147066236023073577355195000846567799556738…

Level H
12.716814692820413523074713233440994231605661201249788358050110815…(from D)+6.132741228718345907701147066236023073577355195000846567799556738…=
18.849555921538759430775860299677017305183016396250634925849667552…

Level I
The solution is identical to 6Pi.
18.849555921538759430775860299677017305183016396250634925849667552…-6pi=0

Since the last result is exactly 6Pi from the approximation 710/113, I wondered if this constructive method is justified to have exacted for the constant factor Pi to match our target.

 

[Cubist]

Posted on behalf of @Atomisphere Alpha

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In my time playing with the calculator, I could find an approximation which might be useful.

The Pi constant factor enigma.

The only codex for the circle unit is beginning with an approximation of…

Level A
710/113-6=0.2831858407079646017699115044247787610619469026548672566371681415…

Level B
We subtract it from the number 4.
4-0.2831853071795864769252867665590057683943387987502116419498891846...=
3.7168146928204135230747132334409942316056612012497883580501108153…
...

Looking at the numbers from your first two steps, you can see that they don't match...

0.2831858407079646017699115044247787610619469026548672566371681415...
0.2831853071795864769252867665590057683943387987502116419498891846...

It was obvious that there would be some trick, because pi is irrational But I kind-of like this trick

 

[Cubist]

Posted on behalf of @Atomisphere Alpha

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I'm sorry I did not see what my notebook's version on my mathematics have incorrectly failed. If you like Sir, you could be interested in this for I do admit it is precious and useful to me from my collections:

"Help me verify this π breakthrough":Algorithm Statement: Let π0=3,Let α=886/283α, πₙ₊₁=sqrt((17288/66666)×10999989×(πₙ /α))/(999999×sqrt(15766509))+(πₙ-(πₙ/α))

Pi spigot formula or just the algebraic form of circular reprise?

Could Pi be one of the secret pin-lock mechanisms if I try to open the peeping keyhole?

(root(43/22×6666/1576509)×1099989)/99999=?

Because I haven't heard nothing anymore from you Sir, I wondered what really is going on in this Forum.

Sincerely Yours,
Greetings.

 

[blamocur]

Because I haven't heard nothing anymore from you Sir, I wondered what really is going on in this Forum.

I felt that @Cubist gave an adequate answer to your post, but in case you are not convinced, here is another detail:

If you combine your manipulations, you will see that the final result is equal not to 0 but to $3*710/113 - 6\pi \approx 0.00000160058513642$