The region between the curves y=x^(2) and y=sqrt of x in QI is the base of a solid.

[on3winyoureyes]

The region between the curves y=x^(2) and y=square root of x in quadrant 1 is the base of a solid. For this solid, each cross section perpendicular to the y-axis is a rectangle whose height (above the xy plane) is half of its length (in the xy-plane). How would you set up this problem if you were to find the volume?

We'd turn in it in terms of y. I'm not sure where the 1/2 goes.

So is it (pi/2 integral from 0 to 1 (square root y-y^(2))

 

[stapel]

The region between the curves y=x^(2) and y=square root of x in quadrant 1 is the base of a solid. For this solid, each cross section perpendicular to the y-axis is a rectangle whose height (above the xy plane) is half of its length (in the xy-plane). How would you set up this problem if you were to find the volume?

We'd turn in it in terms of y. I'm not sure where the 1/2 goes.

So is it (pi/2 integral from 0 to 1 (square root y-y^(2))

I'm not sure what you mean by "turning in it, in terms of y"...? What did you see when you tried drawing a picture of this?