We will create a metal band 4 in. in width, to be able to carry a maximum permitted load of 90 tons. Calculate the thickness of the metal band (as in.) Yield strength of the steel to be used here is equal to 200,000 psi.
Assuming that 1 lb. = 0.45 kg.
sigma(des)=ys/2
A= Pmax/sigma(des)
I get 0,5in when i calculate this, but that must be wrong since noway 0,5 in can support 90tons!:O
Assuming that 1 lb. = 0.45 kg.
sigma(des)=ys/2
A= Pmax/sigma(des)
I get 0,5in when i calculate this, but that must be wrong since noway 0,5 in can support 90tons!:O