tolerance: how to add measurements with tolerances

Paul Suszko

New member
Joined
Dec 6, 2006
Messages
12
I have forgotten how to add the following tolerances:

66 +/- 3.0 g
20 +/- 2.0 g
14 +/- 1.73 g

I am to arrive at a total value of 100 +/- 4.00 g.

Thank you.
 
Square the individual tolerances; add them together; take the square root of the result.
 
Maybe 32+22+(3)2  =  9+4+3  =  16  =  4\displaystyle \sqrt{3^{2}+2^{2}+(\sqrt{3})^{2}}\;=\;\sqrt{9+4+3}\;=\;\sqrt{16}\;=\;4? I wouldn't exactly call that addition, per se.
 
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