Totally stuck: Through the point A(1,5) is drawn line parallel to the x axis to meet

[Kitimbo]

Through the point A(1,5) is drawn a line parallel to the x axis to meet at B the line PQ whose equation is 3y=2x-5.Find the length of AB and the sine of the angle between PQ and AB;hence show that the length of the perpendicular from A to PQ is 18÷√13.Calculate the area of the triangle formed by PQ and the axes.

So here is where I ended
The gradient of AB is 0 so
y-5/x-1=0
y=5
I substituted y=5 into equation of PQ
3(5)=2x-5
x=10
So B=(10,5)
Length AB =√[(10-1)²+(5-5)²]
=9
So I couldn't continue any more.
Please help me coz I have a test tomorrow

 

[Deleted member 4993]

Through the point A(1,5) is drawn a line parallel to the x axis to meet at B the line PQ whose equation is 3y=2x-5.Find the length of AB and the sine of the angle between PQ and AB;hence show that the length of the perpendicular from A to PQ is 18÷√13.Calculate the area of the triangle formed by PQ and the axes.

So here is where I ended
The gradient of AB is 0 so
y-5/x-1=0
y=5
I substituted y=5 into equation of PQ
3(5)=2x-5
x=10
So B=(10,5)
Length AB =√[(10-1)²+(5-5)²]
=9
So I couldn't continue any more.
Please help me coz I have a test tomorrow

What is the slope of the line PQ whose equation is 3y=2x-5?

What is the tan the of the angle between PQ and x-axis?

What is the tan of the angle between PQ and AB?

What is the sine of the angle between PQ and AB?

And continue....