Trapeze

lev888 · Jan 24, 2021

Radit2125 said:
I made a mistake, BC is 2 cm. About the middle one we know that it is equal to CD= 1 cm and the other 2 are also 1 cm.

So, a right triangle has a leg which is half the hypotenuse...

Radit2125 · Jan 24, 2021

This means that AM=BM=1.5 cm

lev888 · Jan 24, 2021

Radit2125 said:
This means that AM=BM=1.5 cm

3 segments total is 3cm. How can 2 of them be 3cm?

Radit2125 · Jan 24, 2021

No, this is not true. I suppose that the two segments (AM=BM) are 2cm

lev888 · Jan 24, 2021

Radit2125 said:
No, this is not true. I suppose that the two segments (AM=BM) are 2cm

To clarify: I am talking about AH, HJ, JB. HJ = 1 (why?). AH+JB=? If AH=JB, then AH=? and JB=?

Radit2125 · Jan 24, 2021

AH=HJ=JB
HJ= 1 cm because HJDC is a rectangle
AH= (AB-CD)/2= (3-1)/2= 1
So, JB= 3-2=1=> AH+JB= 2cm

lev888 · Jan 24, 2021

Radit2125 said:
AH=HJ=JB
HJ= 1 cm because HJDC is a rectangle
AH= (AB-CD)/2= (3-1)/2= 1
So, JB= 3-2=1=> AH+JB= 2cm

Ok, can you continue? AH is? The top angle in each of the right triangle is?