Triangle and figure: In triangle ABC, what is the length of side BC?

[Sykes03]

In triangle ABC above what is the length of side BC?

10^2+8^2= c^2

√100+√64= c^2

answers are (a) 12 (b) 13 (c) 14 (d) 15 and (e) 16 cant figure this out at all


19. The figure above is a floor plan in which all

adjacent sides meet at right angles. What is the
perimeter of the floor? (12 inches = 1 foot)

(A) 27 ft 9 in
(B) 32 ft 9 in

(C) 45 ft 6 in
(D) 55 ft 6 in
(E) 65 ft 3 in



question is number 19 on this link http://www.education.umd.edu/TLPL/programs/CCLTC/docs/Praxis 1 Official Sample Tests math.pdf

 

[Deleted member 4993]

In triangle ABC above what is the length of side BC?

10^2+8^2= c^2

√100+√64= c^2

answers are (a) 12 (b) 13 (c) 14 (d) 15 and (e) 16 cant figure this out at all

19. The figure above is a floor plan in which all

adjacent sides meet at right angles. What is the
perimeter of the floor? (12 inches = 1 foot)

(A) 27 ft 9 in
(B) 32 ft 9 in

(C) 45 ft 6 in
(D) 55 ft 6 in
(E) 65 ft 3 in

question is number 19 on this link http://www.education.umd.edu/TLPL/programs/CCLTC/docs/Praxis 1 Official Sample Tests math.pdf

Let the perpendicular from A (onto BC) intersect BC at O. Then

BO = ?

OC = ?

BC = BO + OC

 

[Sykes03]

confirm

i am confused on your response?

 

[stapel]

B ~
 \    ~   D
  \      ,~  
10 \   8,     ~  
    \  ,     _ _, ~ C
     \,_,- -' 
  
      A

In triangle ABC above (with AD perpendicular to BC, |AB| = 10, |AD| = 8, and the measure of the angle at C being 45°), what is the length of side BC?

10^2+8^2= c^2

√100+√64= c^2

What are the last two lines above? In the first equation, are you maybe trying to solve some right triangle, but messed up the Pythagorean Theorem? In the second equation, are you saying that you're not familiar with how to work with square roots? (One of the first things they'd have taught you would have been that taking roots "does not distribute", is why I ask.)

cant figure this out at all

Your links appear to indicate that you are trying to "study" for a test administered to educators. Have you studied any geometry or algebra at all? We'll be glad to try to help you, but we need to know how far back to go.

floor
plan: *----------------*-
      |                |^
      |                ||
      |                |12 ft 2 in
*-----*                ||
|                      ||
|                      |v
*----------------------*-
|<---- 15 ft 7 in ---->|

19. The figure above is a floor plan in which all adjacent sides meet at right angles. What is the perimeter of the floor? (12 inches = 1 foot)

The "perimeter" is the distance all the way around. Think of taping off the base molding if you're going to re-stain the floor. What linear distance with the painter's tape cover?

What are your thoughts? Please be complete. Thank you!

 

[Sykes03]

reply

I am trying to figure out i know its a squared plus b squared = c squared. its one big triangle but i am confused i know you do the square root but cant figure out how to come up with the answer. and the other figure i believe is 27 ft and 9 inches is that correct. 12 feet + 15 feet = 27 feet and 7 inches plus 2 inches = 9 inches so 27 feet and 9 inches?

 

[stapel]

I am trying to figure out i know its a squared plus b squared = c squared.

I will guess that, by "it", you mean "the Pythagorean Theorem", with "c" being the length of the hypotenuse of the right triangle.

its one big triangle

I will guess that, by "it", you mean "the triangle ABC", rather than either of the right triangles. However, since the Pythagorean Theorem only applies to right triangles, I understand that I may be wrong here. In either case, to what, specifically, are you attempting to apply the Theorem?

but i am confused i know you do the square root

I will guess that, by "do the square root", you mean "one solves the equation for 'c=' by taking the square root of either side of the equation generated by the Theorem". However, this does not explain why you instead took the square roots of each term rather than of each side. This was why I'd asked whether you'd taken any algebra or geometry yet, since you'd have learned how to work with the Theorem in one or both of these classes.

Since you have not responded to that query, I will guess that you are asking for instruction on how to use the Theorem to solve for side lengths. In this case, please try here.

the other figure i believe is 27 ft and 9 inches is that correct.

I will guess that, by "the other figure", you mean "Exercise 19" and that, by "is", you mean "the perimeter of the figure is". However, since your answer value can be obtained by adding the lengths of only two of the walls (rather than, as was explained to you earlier, all of the walls), I must be mistaken.

To learn what "perimeter" is and how to determine it from labelled polygons, try here.

Please study at least two lessons from each of the links before attempting either exercise. If you still get stuck, please reply clearly showing your steps and explaining your reasoning (like I've displayed in my replies). Thank you!