i have a problem understanding the following puzzle (puzzles 101: Yoshigahara)
Triangulation:
A triangle is divided into four parts by two straight lines as shown. The area ratio of the three parts is 3:7:7
What is the size of the fourth area?
solution:
From
S1
S2+7) = 3:7
S2
S1+3))=7:7
we get
S1=7.5 & S2=10.5
so
S1+S2=18
could anyone explain the solution to me? thank you in advance
Triangulation:
A triangle is divided into four parts by two straight lines as shown. The area ratio of the three parts is 3:7:7
What is the size of the fourth area?

solution:
From
S1
S2
we get
S1=7.5 & S2=10.5
so
S1+S2=18

could anyone explain the solution to me? thank you in advance