Trig Equations help how do i find all solutions to sin(5x-pi/4)=-1

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Cheers ~ Mark :cool:
 
ok it asks to find all solutions of sin(5x-pi/4)=-1

i know sin(x) = -1 is 3pi/2 or 270degrees

@mark sorry about that im new on here
 
sin(5x - π/4) = sin[(2*k)*π + 3*π/2] where |k| = 0, 1, 2, 3, .......
 
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Subhotosh Khan said:
sin(5x - π/4) = sin[(2*k)*π + 3*π/2] where |k| = 0, 1, 2, 3, .......
Click to expand...

ok so sin(x) = -1 is at 3pi/2 + 2pi k
i know i set that equal to 5x - pi/4
so i get 5x -pi/4 = 3pi/2 +2pi k
im getting confused do i add pi/4 to both 3pi/2 and 2pi then divide by 5?
 
rrordanes said:
ok so sin(x) = -1 is at 3pi/2 + 2pi k
i know i set that equal to 5x - pi/4
so i get 5x -pi/4 = 3pi/2 +2pi k
im getting confused do i add pi/4 to both 3pi/2 and 2pi then divide by 5?
Click to expand...

If you have:

5x - 4 = 3 + 2*n

How would you solve for 'x'?
 
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