Qwertyuiop[]
Junior Member
- Joined
- Jun 1, 2022
- Messages
- 123
I have come across these 2 questions that i don't know how to solve. [imath]sin\left(x+\frac{\pi }{3}\right)=sin\left(2x\right)[/imath] & [imath]sin (x + \pi/6) = sin (2x + 3\pi/4)[/imath] . When I usually get something like this where there is something inside the brackets , I just set the bracket function equal to let's say, theta and solve for theta and then substitute to find the values of x. So If I have sin (2x + pi/3) = 1/2 I will write this as sin (theta) = 1/2 where theta = (2x + pi/3). Now the problem here is that we have like x + pi/3 and 2x and for the 2nd question x+ pi/6 & 2x + 3pi/4 . What do I do here, can't do 2 substitutions I will end up with 2 variables. I also tried writing sin 2x as 2 sinx cosx but then I get a more complicated expression and then don't know how to proceed, tried factoring but no luck.
So what's the correct approach to this question ?
So what's the correct approach to this question ?