Trig Identities: csc^4(x)-2csc^2(x)+1=cot^4(x)

kwal

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Hi, I have a question from my homework sheet. This one problem is stumping me and I'm a bit confused:
csc^4(x)-2csc^2(x)+1=cot^4(x)

So far I have:
(1/sin^4(x))-(1/2sin^2(x))+1=cos^4(x)/sin^4(x)

If anyone could help me verify the identity that would be great. I tried looking at it on Mathway, because I have a subscription, but there aren't any steps available.
 
Hi, I have a question from my homework sheet. This one problem is stumping me and I'm a bit confused:
csc^4(x)-2csc^2(x)+1=cot^4(x)

So far I have:
(1/sin^4(x))-(1/2sin^2(x))+1=cos^4(x)/sin^4(x)

If anyone could help me verify the identity that would be great. I tried looking at it on Mathway, because I have a subscription, but there aren't any steps available.

Start simplyfying the left-hand-side of the given identity - using csc2(x) = 1 + cot2(x):

csc^4(x)-2csc^2(x)+1

= [1 + cot2(x)]2 - 2*[1 + cot2(x)] + 1

and continue....
 
Hi, I have a question from my homework sheet. This one problem is stumping me and I'm a bit confused: csc^4(x)-2csc^2(x)+1=cot^4(x)

I would note that csc4(x)2csc2(x)+1=(csc2(x)1)2\displaystyle \csc^4(x)-2\csc^2(x)+1=(\csc^2(x)-1)^2
 
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Is this correct?
 

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