Trig identities

[Snowyace]

okay I finally have a correct trig problem lol and I can't solve it. Its a book problem so

csc^2 x sec x = sec x + csc x * cot x

I tried the pythagorean identity but where does the one go? and I get stuck with to many sin's and cos's

 

[Loren]

Start on the right side. Change to cosine and sine. Add and you should get 1/(cos x sin^2 x) and from there???

 

[Snowyace]

separate into 1/ sin^2 x & 1/cos x :?: Then use the reciprical to get the answer

Did I do it right?

 

[mmm4444bot]

separate into 1/ sin^2 x & 1/cos x

Yes, and the proper way to say this:

factor into 1/sin^2(x) * 1/cos(x)



Then use the reciprical to get the answer Use a reciprocal of something? No. We are not dividing by any fractions.

What is 1/sin^2(x), if we write it in terms of cosecant?

What is 1/cos(x), if we write it in terms of secant?