Trig Period problem: Solve tan(x-5)sin(x) = 0 for 0 <= x <= 2pi.

TheSheep

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Dec 10, 2016
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Hello, I am a little confused on this problem.

Solve tan(x-5)sin(x) = 0 for 0 <= x <= 2pi.

I'm not really sure what's going on except that I need to find all of the angels between 0 and 360 degrees. Any help is appreciated! :)
 
You're given that a product of two functions is equal to 0. What does that mean for the value(s) of the functions? As a hint, think about all the ways you can multiply two values together to get 0. You might also find it helpful to brush up on the Zero Product Property (I've also seen it called the Zero Product Principle). Doing this will give you two possible cases for what the values of tan(x - 5) and sin(x) can be. What does it mean if the first case is true? What does it mean if the second case is true? Can both cases be true at the same time? What happens if they are?
 
What does it mean if the first case is true? What does it mean if the second case is true? Can both cases be true at the same time? What happens if they are?
Answering ALL those questions will keep the OP busy for a while:)

Actually those were the perfect questions to ask!
 
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