here's the work i got so far. i guess what im trying to get help for this problem is the last few steps at the end
1. tan15 degrees
tan(A-B)=(tanA-tanB)/(1+tanAtanB)
tan(45-30)=(tan45-tan30)/(1+tan45tan30)
tan(45-30)=[1-(?3/3)]/[(1+1(?3/3)]
tan(45-30)=[1-(?3/3)]/[(1+1(?3/3)]*3
tan(45-30)=(3-?3)/(3+?3)
answer = 2 - ?3
completely stuck on this problem.
2. sin (17pi/12)
Thanks in advance.
1. tan15 degrees
tan(A-B)=(tanA-tanB)/(1+tanAtanB)
tan(45-30)=(tan45-tan30)/(1+tan45tan30)
tan(45-30)=[1-(?3/3)]/[(1+1(?3/3)]
tan(45-30)=[1-(?3/3)]/[(1+1(?3/3)]*3
tan(45-30)=(3-?3)/(3+?3)
answer = 2 - ?3
completely stuck on this problem.
2. sin (17pi/12)
Thanks in advance.