TRIG: 1. If tanC= -0.6687, find C to the nearest degree. 2. cos 59 = x/36. 3. sin 25= 34/x

[yorkmanz]

1)- if tanC= -0.6687 find C to the nearest degree C?


MY ANSWER


-33.77064668


OR SHOULD IT BE -33.80




2)- COS 59 = X/36


X = (COS 59)* (36) =


18.5713707 CORRECT??




3)- sin 25= 34/x

x= (sin 25) * (34) =

14.3690209 correct ???


thanks

 

[ksdhart2]

Your answer for Problem 1 is almost correct, though you should carefully reread the problem text. It says "...to the nearest degree" You correctly found that \(C = \tan^{-1}(-0.6687) \approx -33.7706^{\circ}\). Rounding to -33.8 rounds this to the nearest tenth of a degree, so the nearest degree would be...? Additionally, keep in mind that angles cannot be negative, so think about how you might adjust for this. As a hint, consider the period of the tangent function.

Similarly, your answer for Problem 2 is almost correct but plagued by some rounding errors. It's true that \(X = \cos(59) \cdot 36\) but I'm not quite sure where you got 18.5713... from. According to my calculator, the value is approximately 18.5413. You also should explicitly note in your workings that the 59 and your answer are both in degrees. Without that, we're forced to assume it's in radians, which would make your answer completely incorrect.

 

[yorkmanz]

Sorry mistype the question

Question 1) if tanC= -0.6687 find C to the nearest degree C, C is between 0 and 180 degree?

So my answer

like that

tanC = - 0.6687

tanC IS NEGATIVE

SO MY ANSWER SHOULD BE BETWEEN 90-180

tan(90+A) = -tanA

tanC = tan(90+A) = -0.6687

tan(90+A) = -tanA

-tanA = -0.6687 remove negatives

A = tan^(-1) 0.6687

A = 33.77

C = 90+33.77 = 123.77 degree CORRECT????

 

[yorkmanz]

for question 3)-

3)- sin 25= 34/x

sin5= .423

.423=34/x

.423x=34

x=34/.423

x=80.37 correct?

 

[Deleted member 4993]

Sorry mistype the question

Question 1) if tanC= -0.6687 find C to the nearest degree C, C is between 0 and 180 degree?

So my answer

like that

tanC = - 0.6687

tanC IS NEGATIVE

SO MY ANSWER SHOULD BE BETWEEN 90-180

tan(90+A) = -tanA

tanC = tan(90+A) = -0.6687

tan(90+A) = -tanA

-tanA = -0.6687 remove negatives

A = tan^(-1) 0.6687

A = 33.77

C = 90+33.77 = 123.77 degree CORRECT????

No!

tan(Θ) = tan(180 + Θ) ........Then

C =-33.7706 + 180 = 146.23 =146^o