Trig :/

ballin1225

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Sep 16, 2009
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Two cars make an 8-mile trip. One car has 13-inch-radius tires and the other car has 15-inch-radius tires. Find the number of revolutions (correct to the nearest hundred) each tire makes.
 
ballin1225 said:
Two cars make an 8-mile trip. One car has 13-inch-radius tires and the other car has 15-inch-radius tires. Find the number of revolutions (correct to the nearest hundred) each tire makes.

How much does The center of the circular wheel move horizontally - when it rolls once without slipping on a horizontal plane?
= the circumference of the wheel

What does that tell you?

How can you use that fact in solving the problem?

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.
 
ballin1225 said:
i'm just really not sure how to start the problem.

I am trying to help you to do just that....

Think

and answer my questions.
 
ballin1225 said:
well the circumference of the circle is 360 degrees right?

Circumference of a circle - is same as perimeter - it is a "distance". It cannot be a measure of an angle (360°).

By the way, the problem you posted is not a trig problem.
 
does this sound right?-

1. 8 * 5,250= 42,240 feet
2. 42,240 * 12= 506,880 inches
3. 506,880/ (13* 3.14)=12414
4. 506,880/ (15* 3.14) =10762
 
ballin1225 said:
does this sound right?-

1. 8 * 5,250= 42,240 feet
2. 42,240 * 12= 506,880 inches
3. 506,880/ (13* 3.14)=12414
4. 506,880/ (15* 3.14) =10762

Almost correct - the circumference is 2*pi*r - you have used pi*r

Remember the answers need to be in nearest hundreds.
 
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