L l9876 New member Joined Jun 17, 2010 Messages 2 Jun 17, 2010 #1 Hi Everyone, Can you help me solve the following : 1) Tan (Cos^-1 8/17) 2) Cos (Sin^-13/5 + Sin^-1 5/13) 3) Sec^2(tan^-12) + Cosec^2 (Cot^-1 3) =15
Hi Everyone, Can you help me solve the following : 1) Tan (Cos^-1 8/17) 2) Cos (Sin^-13/5 + Sin^-1 5/13) 3) Sec^2(tan^-12) + Cosec^2 (Cot^-1 3) =15
D Deleted member 4993 Guest Jun 17, 2010 #2 l9876 said: Hi Everyone, Can you help me solve the following : 1) Tan (Cos^-1 8/17) 2) Cos (Sin^-13/5 + Sin^-1 5/13) 3) Sec^2(tan^-12) + Cosec^2 (Cot^-1 3) =15 Click to expand... Yes we can help - if you can show us your work and tell us exactly where you are stuck. We will start you off in the first one: \(\displaystyle \cos^{-1}(x) \ \ = \ \ \theta\) \(\displaystyle \cos(\theta) \ \ = \ \ x\) \(\displaystyle \tan(\theta) \ \ = \ \ \pm \frac{\sqrt{1-x^2}}{x}\) \(\displaystyle \tan(\cos^{-1}(x)) \ \ = \ \ \pm \frac{\sqrt{1-x^2}}{x}\)
l9876 said: Hi Everyone, Can you help me solve the following : 1) Tan (Cos^-1 8/17) 2) Cos (Sin^-13/5 + Sin^-1 5/13) 3) Sec^2(tan^-12) + Cosec^2 (Cot^-1 3) =15 Click to expand... Yes we can help - if you can show us your work and tell us exactly where you are stuck. We will start you off in the first one: \(\displaystyle \cos^{-1}(x) \ \ = \ \ \theta\) \(\displaystyle \cos(\theta) \ \ = \ \ x\) \(\displaystyle \tan(\theta) \ \ = \ \ \pm \frac{\sqrt{1-x^2}}{x}\) \(\displaystyle \tan(\cos^{-1}(x)) \ \ = \ \ \pm \frac{\sqrt{1-x^2}}{x}\)
