trigonofinity...

[sabdani]

hello guyz...
im the newest...
reading all your forums here was very great...
lots of here are math wizards ahh...
hope i can be one of you...
anyway...
this is my trivia for you...
i know its very easy for you...
just want to share something...

what would be the answer?...

1 + ((tan 1 degree+tan 2 degrees+...tan 89degress)/(tan 91 degrees)+(tan 92 degrees+...tan 179 degrees))

please observe the parenthesis used...

 

[jsbeckton]

Do you want the exact anwser? If so you need to convert to radians, its much easier to work with although this seems more like a calculator problem to me, if you are working with exact anwser you are almost certainally going to get a crazy fraction. Also, the way that the parenthesis are used is very unclear. you need to use double (()) around the whole numerator and the whole denomanitor.

I took it as:\(\displaystyle 1 + \frac{{\tan (1) + \tan (2) + \tan (89)}}{{\tan (91) + \tan (92) + \tan (179)}}\) , plugged it into my ti-89 and got a crazy trig fraction thats not even worth copying down.

 

[jsbeckton]

Do you want the exact anwser? If so you need to convert to radians, its much easier to work with although this seems more like a calculator problem to me, if you are working with exact anwser you are almost certainally going to get a crazy fraction. Also, the way that the parenthesis are used is very unclear. you need to use double (()) around the whole numerator and the whole denomanitor.

I took it as:\(\displaystyle 1 + \frac{{\tan (1) + \tan (2) + \tan (89)}}{{\tan (91) + \tan (92) + \tan (179)}}\) , plugged it into my ti-89 and got a crazy trig fraction thats not even worth copying down.

The decimal anwser is .99876

 

[soroban]

Hello, all!

Didn't anyone notice the "three dots"??


\(\displaystyle 1\;+\;\frac{\tan1^o\,+\,\tan2^o\,+\,\tan3^o\,+\,\cdots\,+\,\tan89^o}{\tan91^o\,+\,\tan92^o\,+\,\tan93^o\,+\,\cdots\,+\,\tan179^o}\)


Since \(\displaystyle \tan(180^o\,-\,\theta)\:=\;-\tan\theta\), then:

. . \(\displaystyle \tan91^o\,=\,-\tan89^o\)
. . \(\displaystyle \tan92^o\,=\,-\tan88^o\)
. . \(\displaystyle \tan93^o\,=\,-\tan87^o\)
. . . . \(\displaystyle \vdots\;\;\;\;\;\;\;\;\;\vdots\)
. . \(\displaystyle \tan179^o\,=\,-\tan1^o\)

The denominator is the <u>negative</u> of the numerator!


Therefore, we have: \(\displaystyle \;1\,+\,(-1) \;=\;0\)

 

[stapel]

Didn't anyone notice the "three dots"??

It's the little things in life that trip us up.... :wink:

Eliz.

 

[Lizzie]

This is very true...although I should probably shut up because I don't remember how the heck to do any of this, lol.

 

[sabdani]

logafinity...

you are all great!!
the correct answer is zero...

try this another one...
please...
no calculators...
just use your math knowledge...


the logarithm of x raised to x raised to x raised to x...(infinity) to the base 10 is five.

what is the value of x?

 

[stapel]

Re: logafinity...

try this another one...

Please post new exercises as new threads, not as replies to old questions.

When you re-post this, please include all of the steps and reasoning you have attempted thus far, stating clearly where you are stuck.

Thank you.

Eliz.