Trigonometic derivatives

[Dorian Gray]

Good Morning/Good Evening Mathematicians,

I am having issues with this problem: y=sin[tan(radical sinx)].


I seem to be having difficulties simplifying my answer (assuming that I did not make a mistake in the work). Please let me know if you see something that I am missing. Any and all input is much appreciated.



Regards,
D

 

[Unknown008]

Uhm... I'm not sure why you used the product rule...

Generally, it's:

\(\displaystyle y = \sin(f(x))\)

\(\displaystyle y' = \cos(f(x)) \cdot f'(x)\)

Right? Same applies to tan.

\(\displaystyle y = \tan(f(x))\)

\(\displaystyle y' = \sec^2(f(x)) \cdot f'(x)\)

Could you try again?