Trigonometry headache, any ideas?

[Funkadelia]

Another one! Thanks...

It's a roof beam problem - see attached

I've had a go at question a) but b), c) and d) are defeating me.

Any ideas? Thanks

 

[Deleted member 4993]

Another one! Thanks...

It's a roof beam problem - see attached

I've had a go at question a) but b), c) and d) are defeating me.

Any ideas? Thanks

If we can assume, mCGA = 90°, then AC = 3/cos²(30°) = 4 → AE = 8 (from symmetry)

 

[Funkadelia]

Subhotosh, thank you so much for your help - it really is very much appreciated!