S sailor79 New member Joined Jan 16, 2012 Messages 1 Jan 16, 2012 #1 Hi, I'm lacking enough math knowledge to solve this probably simple problem. I need to solve the following formula for y: x = (180/PI) * Ln(tan(45 + y/2)) Hope someone can help me here.
Hi, I'm lacking enough math knowledge to solve this probably simple problem. I need to solve the following formula for y: x = (180/PI) * Ln(tan(45 + y/2)) Hope someone can help me here.
D Deleted member 4993 Guest Jan 16, 2012 #2 sailor79 said: Hi, I'm lacking enough math knowledge to solve this probably simple problem. I need to solve the following formula for y: x = (180/PI) * Ln(tan(45 + y/2)) Hope someone can help me here. Click to expand... Have you learned inverse operations: Inverse of addition is subtraction. Inverse of multiplication is division. Inverse of logarithm [Ln(x)] is exponential (ex). Inverse of tangent function[tan(x)] is tan_inverse function [tan-1(x)]. You will have to use these ...... it will look complicated but straight-forward operation. Start with: \(\displaystyle x = \frac{180}{\pi}*Ln[tan(45+\frac{y}{2})]\) \(\displaystyle x * \frac{\pi}{180} \ = \ Ln[tan(45+\frac{y}{2})]\) Now invert LN .... then invert tan.... and so on.... Last edited by a moderator: Jan 16, 2012
sailor79 said: Hi, I'm lacking enough math knowledge to solve this probably simple problem. I need to solve the following formula for y: x = (180/PI) * Ln(tan(45 + y/2)) Hope someone can help me here. Click to expand... Have you learned inverse operations: Inverse of addition is subtraction. Inverse of multiplication is division. Inverse of logarithm [Ln(x)] is exponential (ex). Inverse of tangent function[tan(x)] is tan_inverse function [tan-1(x)]. You will have to use these ...... it will look complicated but straight-forward operation. Start with: \(\displaystyle x = \frac{180}{\pi}*Ln[tan(45+\frac{y}{2})]\) \(\displaystyle x * \frac{\pi}{180} \ = \ Ln[tan(45+\frac{y}{2})]\) Now invert LN .... then invert tan.... and so on....
