trigonometry (symmetry arguments and trig identities)

ripple

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Mar 15, 2017
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Hey guys,
Got this question on an assignment and have no idea what to do.

1. Show that the following relationships are true
(i) cos(θ − 180) = −cos(θ) using symmetry arguments
(ii) sin(θ − 180) = −sin(θ) using symmetry arguments
(iii) Confirm the relationships in parts (i) and (ii) using trigonometric identities

I have no idea how to use symmetry arguments or how to present them.
Also (iii) asks me to confirm these relationships using trig identities, I thought they were already using trig identities.
Thanks for any help in advance
 
I'm not familiar with the term "symmetry arguments," but my best guess is that it's talking about how sine is an odd function so -sin(t) = sin(-t) for any t, and cosine is an even function so cos(t) = cos(-t) for any t. If this is not correct, please reply with the definition as given by your class/textbook/instructor. For now, I'll assume my definition is correct...

To work the proofs, I'd begin by noting that an extension of the symmetry arguments tells you that sin(t) = -sin(-t). If we let t=θ+180\displaystyle t=\theta+180^{\circ}, then we have cos(θ+180)=cos((θ+180))    cos(θ+180)=cos(θ180)\displaystyle cos(\theta+180^{\circ})=cos(-(\theta+180^{\circ})) \implies cos(\theta+180^{\circ})=cos(-\theta-180^{\circ}) and sin(θ+180)=sin((θ+180))    sin(θ+180)=sin(θ180)\displaystyle sin(\theta + 180^{\circ})=-sin(-(\theta+180^{\circ})) \implies sin(\theta + 180^{\circ})=-sin(-\theta - 180^{\circ}). Where do those lead you?

Then for the third part, I agree with your assessment that they're already identities in their own right, but I suspect you're being asked to proof them by starting from more "basic" identities. In this case, you might use sin(θ+90)=cos(θ)\displaystyle sin(\theta+90^{\circ})=cos(\theta) and cos(θ+90)=sin(θ))\displaystyle cos(\theta+90^{\circ})=-sin(\theta)), along with sin(a+b)=sin(a)cos(b)+cos(a)sin(b)\displaystyle sin(a+b)=sin(a) cos(b) + cos(a) sin(b) and cos(a+b)=cos(a)cos(b)sin(a)sin(b)\displaystyle cos(a+b)=cos(a) cos(b) - sin(a) sin(b). When using these identities, keep in mind that θ+180=(θ+90)+90\displaystyle \theta+180^{\circ}=(\theta+90^{\circ})+90^{\circ}. Where does all of this lead you?
 
Hey guys,
Got this question on an assignment and have no idea what to do.

1. Show that the following relationships are true
(i) cos(θ − 180) = −cos(θ) using symmetry arguments
(ii) sin(θ − 180) = −sin(θ) using symmetry arguments
(iii) Confirm the relationships in parts (i) and (ii) using trigonometric identities

I have no idea how to use symmetry arguments or how to present them.
Also (iii) asks me to confirm these relationships using trig identities, I thought they were already using trig identities.
Thanks for any help in advance
(iii) Confirm the relationships in parts (i) and (ii) using trigonometric identities

I think you would need to use:

sin(A - B) = sin(A) * cos(B) - cos(A) * sin(B) &

sin(180°) = 0 & cos(180°) = -1
 
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