[EDIT: solved]
Find the volume using triple integrals for the wedge of the cylinder x2 + 4y2 = 4 created by the planes z = 3-x and z = x-3
I tried writing the bounds as -2<= x <= 2, -1 <= y <= 1, x-3 <= z <= 3-x
and then the integral as int(-2..2),int(-1..1),int(x-3..3-x) 1 dzdydx, but then found that the answer is 12pi. I don't understand how to implement the polar form when the figure is an ellipse and spans all 8 octants apparently. I think I'm supposed to split it? Thanks
Find the volume using triple integrals for the wedge of the cylinder x2 + 4y2 = 4 created by the planes z = 3-x and z = x-3
I tried writing the bounds as -2<= x <= 2, -1 <= y <= 1, x-3 <= z <= 3-x
and then the integral as int(-2..2),int(-1..1),int(x-3..3-x) 1 dzdydx, but then found that the answer is 12pi. I don't understand how to implement the polar form when the figure is an ellipse and spans all 8 octants apparently. I think I'm supposed to split it? Thanks
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