Hello! It's true? 30<a≤120. (30<a≤120)/2. 15>a/2≥60.
M MSE New member Joined Feb 28, 2021 Messages 11 Mar 15, 2021 #1 Hello! It's true? 30<a≤120. (30<a≤120)/2. 15>a/2≥60.
Cubist Senior Member Joined Oct 29, 2019 Messages 1,666 Mar 15, 2021 #2 Why did you change the direction of the "<" and "≤" ?
Cubist Senior Member Joined Oct 29, 2019 Messages 1,666 Mar 15, 2021 #4 MSE said: So, it's true↓? 15<a/2≤60. Click to expand... Yarp ! But why did you divide by 2? Why not leave it as 30<a≤120 which is pretty easy to comprehend!
MSE said: So, it's true↓? 15<a/2≤60. Click to expand... Yarp ! But why did you divide by 2? Why not leave it as 30<a≤120 which is pretty easy to comprehend!
Cubist Senior Member Joined Oct 29, 2019 Messages 1,666 Mar 15, 2021 #5 NOTE: Normally you swap the direction of inequalities only when multiplying or dividing throughout by a negative amount.
NOTE: Normally you swap the direction of inequalities only when multiplying or dividing throughout by a negative amount.
M MSE New member Joined Feb 28, 2021 Messages 11 Mar 15, 2021 #6 Cubist said: Yarp ! But why did you divide by 2? Why not leave it as 30<a≤120 which is pretty easy to comprehend! Click to expand... Cubist said: NOTE: Normally you swap the direction of inequalities only when multiplying or dividing throughout by a negative amount. Click to expand... Thanks!
Cubist said: Yarp ! But why did you divide by 2? Why not leave it as 30<a≤120 which is pretty easy to comprehend! Click to expand... Cubist said: NOTE: Normally you swap the direction of inequalities only when multiplying or dividing throughout by a negative amount. Click to expand... Thanks!
J JeffM Elite Member Joined Sep 14, 2012 Messages 7,874 Mar 16, 2021 #7 There is another reason to swap the direction of inequalities, which may have lead you astray. [MATH]0 < a < b \iff \dfrac{1}{a} > \dfrac{1}{b} > 0.[/MATH]
There is another reason to swap the direction of inequalities, which may have lead you astray. [MATH]0 < a < b \iff \dfrac{1}{a} > \dfrac{1}{b} > 0.[/MATH]
