Two velocity equations rewritten as one

Are you posting an assignment directly. As such, it does not make sense. Below the figure you write:

d = distance = x2 0 ≤ x ≤ a

but then you write "velocity = x2 feet/sec"

Which is it?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

READ BEFORE POSTING

Please share your work/thoughts about this problem.

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No one here will even consider to show you the steps to solve your problem. You have posted long enough to know that by now.
The way it works is that you show us your work and we push nudge you in the right direction.
 
Are you posting an assignment directly. As such, it does not make sense. Below the figure you write:

d = distance = x2 0 ≤ x ≤ a

but then you write "velocity = x2 feet/sec"

Which is it?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

READ BEFORE POSTING

Please share your work/thoughts about this problem.

View attachment 22125
1602121926472.png
 
Why add them together? They are only valid on different intervals.

You state that you want a single equation but you fail to say for what? A single equation for the velocity? Or for the distance? Or maybe the acceleration?

Do you notice that after taking the integral and then the derivative you just ended up adding x^2 and 2x-1. You do have an error in your work however. You lost the 3 in x^2/3 when you added the two integrals.
 
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