I tried solving the following problem with u=x^(1/3)-1 and I did not get the book solution. So then I tried u=x^(1/3) and it matched the book. Why is my first attempt wrong? Thank you!
I tried solving the following problem with u=x^(1/3)-1 and I did not get the book solution. So then I tried u=x^(1/3) and it matched the book. Why is my first attempt wrong? Thank you! View attachment 26047
The top attempt has an extra 3 in the first term, and otherwise looks good.
In the bottom attempt, if \(u = \sqrt[3]{x}-1\), then \(x = (u+1)^3\) so \(dx = 3(u+1)^2du\), not \(3u^2du\).
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