G
Guest
Guest
Ok so the question asks:
Find the marked angle in the following triangles in degrees, minutes and seconds.
So there's a picture of a triangle,
one side is 51m long,
another is 75m long
nd you get the area which = 1683m^2
and you have to work out the angle between the two sides your given using...
Area=1/2bcsinA
This is what I've got so far...
Area=1/2bcsinA
1683=1/2x51x75xsinA
sinA=1683
1/2x51x75
So the answer I got was sinA=0 degrees 52'48"
but that's not the right answer.
Some how I have to get to...
61 degrees 39' or 118 degree s21' as my answer
but I don't know how!
Possibly you could tell me how to put it into my calculator for future referance my half yearly is on Tuesday!
Thanks alot if you can help me I streesing soo bad!
Find the marked angle in the following triangles in degrees, minutes and seconds.
So there's a picture of a triangle,
one side is 51m long,
another is 75m long
nd you get the area which = 1683m^2
and you have to work out the angle between the two sides your given using...
Area=1/2bcsinA
This is what I've got so far...
Area=1/2bcsinA
1683=1/2x51x75xsinA
sinA=1683
1/2x51x75
So the answer I got was sinA=0 degrees 52'48"
but that's not the right answer.
Some how I have to get to...
61 degrees 39' or 118 degree s21' as my answer
but I don't know how!
Possibly you could tell me how to put it into my calculator for future referance my half yearly is on Tuesday!
Thanks alot if you can help me I streesing soo bad!