Using the quadratic formula part 3?

confused20

New member
Joined
Mar 9, 2008
Messages
5
Thank you to the 2 individuals who have responded to my previous post. If anyone could help me with the following problem, it would greatly be appreciated.

X/(.20-X)^2 = 4.9 x 10^-4

Thank you for any input on the above questions. Have a great day.
 
I am going to use fractions instead of decimals.

x(15x)2=49100,000\displaystyle \frac{x}{(\frac{1}{5}-x)^{2}}=\frac{49}{100,000}

Cross multiply:

100,000x=49(15x)2\displaystyle 100,000x=49(\frac{1}{5}-x)^{2}

Now, expand and bring everything to one side setting to 0 and then you have another quadratic to solve.
 
confused20 said:
Thank you to the 2 individuals who have responded to my previous post. If anyone could help me with the following problem, it would greatly be appreciated.

X/(.20-X)^2 = 4.9 x 10^-4
Why not multiply through, as was suggested in one of those earlier threads?

Eliz.
 
Top