variation problem

jem3

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Apr 27, 2009
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If a man who is 5 feet 10 inches tall weighs 170 pounds how much does a man of the same body type who is 8 feet 2 inches tall weigh?

I'm not sure what to do with this variation problem. I converted the heights into inches and plugged the
weight and heights given into the formula y=kx^3, but I can't seam to get a reasonable answer. Perhaps I'm
using the wrong formula or I'm just plugging the information in wrong. Anyway, I can't seam to get it right.

Here's what I've tried: 5'10"=70inches and 8'2"=98inches
y=170 k(70^3)
170=34000
K=170/34000k
y=(170/34000k)(98^3)
y=4705.96?
 
jem3 said:
If a man who is 5 feet 10 inches tall weighs 170 pounds how much does a man of the same body type who is 8 feet 2 inches tall weigh?

I'm not sure what to do with this variation problem. I converted the heights into inches and plugged the
weight and heights given into the formula y=kx^3 <<< where did you get that, but I can't seam to get a reasonable answer. Perhaps I'm
using the wrong formula or I'm just plugging the information in wrong. Anyway, I can't seam to get it right.

Here's what I've tried: 5'10"=70inches and 8'2"=98inches
y=170 k(70^3)
170=34000
K=170/34000k
y=(170/34000k)(98^3)
y=4705.96?
Even if the equation is correct - you are making severe mistakes in your number manipulation.

Please see a face-to-face tutor to get the process straightened out.
 
jem3 said:
Here's what I've tried: 5'10"=70inches and 8'2"=98inches
y=170 k(70^3)
170=34000
K=170/34000k
y=(170/34000k)(98^3)
y=4705.96?
Jem, a little bit of common sense will tell you that if 70 inches = 170 pounds,
then 98 inches is a little higher...BUT certainly NOT 4706 pounds :shock:

HINT: if 70 inches = 170 pounds, then 1 inch = ???
 
Denis said:
jem3 said:
Here's what I've tried: 5'10"=70inches and 8'2"=98inches
y=170 k(70^3)
170=34000
K=170/34000k
y=(170/34000k)(98^3)
y=4705.96?
Jem, a little bit of common sense will tell you that if 70 inches = 170 pounds,
then 98 inches is a little higher...BUT certainly NOT 4706 pounds :shock:

HINT: if 70 inches = 170 pounds, then 1 inch = ??? <<< are you assuming linear proportionality?
 
Subhotosh Khan said:
HINT: if 70 inches = 170 pounds, then 1 inch = ??? <<< are you assuming linear proportionality?
Of course...at the level the student seems to be at :wink:
 
jem3 said:
If a man who is 5 feet 10 inches tall weighs 170 pounds how much does a man of the same body type who is 8 feet 2 inches tall weigh?

I'm not sure what to do with this variation problem. I converted the heights into inches and plugged the
weight and heights given into the formula y=kx^3, but I can't seam to get a reasonable answer. Perhaps I'm
using the wrong formula or I'm just plugging the information in wrong. Anyway, I can't seam to get it right.

Here's what I've tried: 5'10"=70inches and 8'2"=98inches
y=170 k(70^3)
170=34000
K=170/34000k
y=(170/34000k)(98^3)
y=4705.96?

If two figures are SIMILAR (and "same body type" would indicate that), then the ratio of the volumes of the figures is the CUBE of the ratio of a pair of corresponding lengths.

Suppose figures 1 and 2 are similar, that h[sub:1teoyjoo]1[/sub:1teoyjoo] represents the height of figure 1, and that h[sub:1teoyjoo]2[/sub:1teoyjoo] represents the height of figure 2.

Then, the ratio of corresponding lengths is h[sub:1teoyjoo]1[/sub:1teoyjoo] / h[sub:1teoyjoo]2[/sub:1teoyjoo].

Let V[sub:1teoyjoo]1[/sub:1teoyjoo] = volume (or weight, in this problem) of figure 1, and let V[sub:1teoyjoo]2[/sub:1teoyjoo] = volume (or weight) of figure 2.

Since the ratio of the volumes of two similar figures is the CUBE of the ratio of a pair of corresponding lengths,

V[sub:1teoyjoo]1[/sub:1teoyjoo] / V[sub:1teoyjoo]2[/sub:1teoyjoo] = (h[sub:1teoyjoo]1[/sub:1teoyjoo] / h[sub:1teoyjoo]2[/sub:1teoyjoo])[sup:1teoyjoo]3[/sup:1teoyjoo]


Now, you know the first man is 5 feet 10 inches tall...let's convert that to inches: 5*12 inches + 10 inches = 70 inches

The questioned person is 8 feet 2 inches tall...convert that to inches, also: 8*12 inches + 2 inches = 98 inches

Then h[sub:1teoyjoo]1[/sub:1teoyjoo] = 70 inches and h[sub:1teoyjoo]2[/sub:1teoyjoo] = 98 inches.

The weight (volume) of the man is 170 lbs...that's V[sub:1teoyjoo]1[/sub:1teoyjoo]
We don't know the weight of the "really tall" man...call that "x"

Substitute into the formula.

V[sub:1teoyjoo]1[/sub:1teoyjoo] / V[sub:1teoyjoo]2[/sub:1teoyjoo] = (h[sub:1teoyjoo]1[/sub:1teoyjoo] / h[sub:1teoyjoo]2[/sub:1teoyjoo])[sup:1teoyjoo]3[/sup:1teoyjoo]

150 / x = (70/98)[sup:1teoyjoo]3[/sup:1teoyjoo]

Now, solving for x is up to you.
 
Aladdin said:
238 pounds
Under standard conditions (as explained in a previous reply, and as reflected in the equation provided by the original poster), this value is incorrect. :?
 
Thanks to all who responded to my question, your help was greatly appreciated. I knew the anwers I kept getting could not possibly be right, but the tips and suggestions you guys provided helped clear things up...you guys explained it so much better than how my book does. At first glance I didn't think it would be that hard of a problem, but sometimes I have a habit of making things more difficult than they have to be. Out of all things Algebra, I find word problems the most challenging simply because I am not very good at translating the language of Algebra into English. Thanks again. Jem3
 
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