vertical asymptotes of f(x)= 2x/x(x-6)(x+1)

[dayton1]

I was asked what the asymptotes of this simplified equation:
f(x)= 2x/x(x-6)(x+1)

I said that the asymptotes are 0, 6 and -1.......but I am wrong I guess.....any help

 

[skeeter]

the vertical asymptotes are x = 6 and x = -1. there is a removable discontinuity {a "hole"} at x = 0.

 

[dayton1]

Thanks