Volume and total surface

[missmissy]

hey everyone im new here and i really need help with this i dont understand at all...


1.) If the bottom of the box is to be a square and the height is to be 20 inches, what will the dimensions of the bottom be?


2.) If a shipping box is to have a fixed volume of 600 cubic inches, what equations would be convenient for calculating the following?

-required height for many different combinations of length anf width

-required length for many different combinations of height and width

-required width for many different combinations of height and length



thank you!!

 

[missmissy]

please someone, anyone!

 

[tkhunny]

Ummm... You have provided only part of the problem statement.

Have some patience. We will get to you MUCH faster if you write a clear AN COMPLETE problem statement AND show what you have tried. We can help much better if we know what we are working with.

 

[Mrspi]

hey everyone im new here and i really need help with this i dont understand at all...


1.) If the bottom of the box is to be a square and the height is to be 20 inches, what will the dimensions of the bottom be?


2.) If a shipping box is to have a fixed volume of 600 cubic inches, what equations would be convenient for calculating the following?

-required height for many different combinations of length anf width

-required length for many different combinations of height and width

-required width for many different combinations of height and length



thank you!!

1) Were you given some other information on this one? If the base is a square, and you let x = the length of one side of this square, then
Volume = 20*x*x
and
Surface area = 20*4x + x<SUP>2</SUP>

If you are given either the surface area or the volume, substitute it into the appropriate equation and solve for x.

2) We know that for a "box"
Volume = length*width*height

If you let L = length, W = width, and H = height, then
Volume = LWH

This box has a volume of 600 in<SUP>3</SUP>. So,
600 = LWH

If you are going to be determining the "required height for many different combinations of length and width", then I think you would want the above equation to be in the form "H = something". Solve for H:
600/(LW) = H

You should be able to figure out the other two now.