The solid lies between planes perpendicular to the x axis at \(\displaystyle x = -1\) and \(\displaystyle x = 1\). The cross-sections perpendicular to the x axis between these planes are squares whose bases run from the semi-circle \(\displaystyle y = -\sqrt{1 - x^{2}}\) to the semi-circle \(\displaystyle y = \sqrt{1 - x^{2}}\)
\(\displaystyle V = \int_{a}^{b} A(x) dx\)
\(\displaystyle x^{2}\) is the area of a square
\(\displaystyle A = x^{2}\)
\(\displaystyle V = \int_{-1}^{1} [2 \sqrt{1 - x^{2}}]^{2}\)
\(\displaystyle V = \int_{-1}^{1} [4 (1 - x^{2})]\)
\(\displaystyle V = \int_{-1}^{1} 4 - 4x^{2}\)
The book says the answer will come out to \(\displaystyle \dfrac{16}{3}\)
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